sh*shqa

Jun 20, 2023

$A$ – cамосопряженный оператор

$H = \overline{\operatorname{Im}A_{\lambda}} \oplus \operatorname{Ker}A_{\lambda}$

Док-во

  • Опираемся на decomposition-theorem-for-operator
  • $(A_\lambda)^* = (A - \lambda I)^* = A^* - \overline{\lambda} I = A - \overline{\lambda} I$
Made by @shishqa